physics class 11 chapter 2

Class 11 Physics Chapter 2 Units and Measurement Notes aims at increasing the self-confidence of the students by offering a simple way to study or revise the chapter. NCERT solutions for Class 11 Physics Chapter 2 Units and measurement is the best study resource you can get to understand the topics and to score good grades in your class 11 final examination. You will also understand the need for S.I. 2.8 Answer the following :(a)You are given a thread and a metre scale. Along with the textbook question, this solution has exemplary problems, worksheets, questions from previous question papers, … Chapter 6. In this chapter, we focus on the core concepts and the foundation of physics. What is the total atomic volume in m3 of a mole of hydrogen atoms? How much parallax would this star (named Alpha Centauri) show when viewed from two locations of the Earth six months apart in its orbit around the Sun? Let's then use these as the foundation to learn about centre of mass, rotational motion, gravitation, solids, fluids, thermodynamics, and oscillations and waves. Class 11 Physics Notes Pdf: We know that last-minute revision and stuffing is never so easy during examinations. Prepare online for FSc part 1, 11th class Physics Chapter 2 online mcq test with answers pdf, FSc Part 1 Book 1 Physics Chapter 2 Vectors and Equilibrium UNITS AND MEASUREMENTS . Physics 1st Year All Chapter Notes | Physics FSc Part 1 ” Class 11 Physics Notes “ Physics-XI (Punjab Text Book Board, Lahore) These Physics-XI FSc Part 1 (1st year) Notes are according to “Punjab Text Book Board, Lahore”. Cloudflare Ray ID: 5fd213895a9dd925 NCERT Grade 11 Physics Chapter 2, Units and Measurement, deals with minute and large ranges of length and mass measurement. He makes 20 observations and finds that the average width of the hair in the field of view of the microscope is 3.5 mm. We also share useful articles on our facebook page to help you in your board examination. Number of strands of hair = Total  surface  areaarea  of  one  hair\frac{Total\;surface\;area}{area\;of\;one\;hair}areaofonehairTotalsurfacearea​ = Ar2\frac{A}{r^{2}}r2A​, In mole, the number of molecules = 6.023 x 1023, Number of molecules in room = 6.023×102322.4×10−3\frac{6.023\times 10^{23}}{22.4\times 10^{-3}}22.4×10−36.023×1023​ = 134.915 x 1026 V. 2.23 The Sun is a hot plasma (ionized matter) with its inner core at a temperature exceeding 107 K, and its outer surface at a temperature of about 6000 K. At these high temperatures, no substance remains in a solid or liquid phase. Since 1 is the least number of decimal places, the total mass = 2.7 kg. Chapter 4. The density is in the range of solids and liquids. If you have any doubt, please visit to DISCUSSION FORUM to ask your questions and reply to the questions already asked by your friends and other users. (b) the difference in the masses of the pieces to correct significant figures? NCERT Solutions for Class 11-science Physics CBSE, 2 Units and Measurements. As the wind blows, it rotates the anemometer and the number of rotations per second gives the wind speed. Class 11 Physics NCERT Solutions Physics is the natural science that studies the matter and its motion and behavior through space and time and that studies the related entities of energy and force. (b) 1 m = ….. ly It is the distance of an object that will show a parallax of 1” (second of arc) from opposite ends of a baseline equal to the distance from the Earth to the Sun. (d) y = a2a\sqrt{2}a2​ ( sin 2πtT\frac{2\pi t}{T}T2πt​ + cos2πtT\frac{2\pi t}{T}T2πt​ ). We can come to the conclusion that the optical instrument is the most precise device used to measure length. How will you estimate the diameter of the thread? CBSE Class 11 Physics Chapter-wise NCERT Solutions. (cm)3s–2 g–1, => 6.67 x 10-11 Nm2 kg-2 = 6.67 x 10-11 x (1kg m s -2) (1m2) (1kg-2). (a) The volume of a cube of side 1 cm is equal to …..m3, = 1100\frac{1}{100}1001​ m×\times×1100\frac{1}{100}1001​ m×\times×1100\frac{1}{100}1001​ m, (b) The surface area of a solid cylinder of radius 2.0 cm and height 10.0 cm is equal to …(mm)2, Surface area of a cylinder = 2π\piπr(r + h). (d) the air inside this room contains a large number of molecules We have lots of study material written in easy language that is easy to follow. The slide is projected on to a screen, and the area of the house on the screen is 1.55 m2. 2.22 Just as precise measurements are necessary for science, it is equally important to be able to make rough estimates of quantities using rudimentary ideas and common observations. X-ray spectroscopy is used to find the interatomic separation. (c) A vehicle moving with a speed of 18 km h–1 covers….m in 1 s, The speed of the car is said to be 18 km/hr = 18 x 1000/3600 meter/second, => 5 m/s, this means that the car covers 5 meters in one second = 11.3. If you are at an office or shared network, you can ask the network administrator to run a scan across the network looking for misconfigured or infected devices. By increasing the number of divisions on the circular scale can the accuracy be increased? Notes Exercise Numerical Problems Important MCQs. Area of the house in the photo = 2.75 cm2, Area of the house on the screen = 2.45 m2 = 2.45 x 104 cm2, Arial magnification, ma = Area  of  imagearea  of  object\frac{Area\;of\;image}{area\;of\;object}areaofobjectAreaofimage​ = 2.452.75\frac{2.45}{2.75}2.752.45​ x 104, Linear magnification m1 = ma\sqrt{m_{a}}ma​​ = 2.452.75×104\sqrt{\frac{2.45}{2.75}\times 10^{4}}2.752.45​×104​ =  94.38, 2.10 State the number of significant figures in the following :(a) 0.007 m2(b) 2.64 × 1024 kg(c) 0.2370 g cm–3(d) 6.320 J(e) 6.032 N m–2(f) 0.0006032 m2. This solution provides appropriate answers to the questions provided in the textbook. Class 11 Chapter - 2 Physics will strengthen the basic concepts of the following topics. Board: Central Board of Secondary Education(www.cbse.nic.in) Subject: Class 11 Physics Number of Worksheets: 103. units and how they are decided in this chapter. What is the estimate on the thickness of the hair? That is, the baseline is about the diameter of the Earth’s orbit ≈ 3 × 1011m. Now measure the depth of the ship with an elephant onboard. Along with the textbook question, this solution has exemplary problems, worksheets, questions from previous question papers, numerical problems, MCQs, short answer questions, tips and tricks. Why is this ratio so large? NCERT Book for Class 11 Physics Chapter 2 Units and Measurements is available for reading or download on this page. The baseline AB is the line joining the Earth’s two locations six months apart in its orbit around the Sun. The above relation shows that r0 constant depends on nucleus mass. The digits 2, 6, and 4 are significant figures. Why is that? • Since the given value is below one, the zeros on the right side of the decimals are insignificant. LAWS OF MOTION . Chapter 5. Answer: When the values are put together, we get: 1kg x 1m2 x 1s-2 = 103g x (102cm)2 x 1s-2  = 103g x 104 cm2 x 1s-2  = 107 gcm2s-2, Time = 1 yr = 365 days = 365 x 24 hr = 365 x 24 x 60 x 60 sec. CBSE Class 11 Physics Chapter 2 – Units and Measurement Class 11 Notes. The area has five significant values 1, 2, 4, 8 and 4. Digital NCERT Books Class 11 Physics pdf are always handy to use when you do not have access to physical copy. BYJU also provides notes, study materials, numerical problems, previous year question papers, sample papers and competitive exam study materials to help you score good marks in the Class 11 examination and competitive examinations. How to use this page to learn physics You are here in this page means you are looking for something to help you study physics of class 11. These chapter wise test papers for Class 11 Physics will be useful to test your conceptual understanding. Chapter 3. Students who are in class 11th or preparing for any exam which is based on Class 11 Physics can refer NCERT Physics Book for their preparation. Units and Measurement Class 11 Notes Physics Chapter 2. Required fields are marked *. All the CBSE Worksheets for Class 11 Physics provided in this page are provided for free which can be downloaded by students, teachers … (e) a proton is much more massive than an electron What is the percentage error in the quantity P? Physics Class 11 Important Questions are very helpful to score high marks in board exams.Here we have covered Important Questions on all topics for Class 11 physics subject. 2.14 A book with many printing errors contains four different formulas for the displacement y of a particle undergoing a certain periodic motion: (a) y = a sin (2πtT\frac{2\pi t}{T}T2πt​), (c) y = aT\frac{a}{T}Ta​ sin ta\frac{t}{a}at​, (d) y = a2a\sqrt{2}a2​ ( sin 2πtT\frac{2\pi t}{T}T2πt​ + cos 2πtT\frac{2\pi t}{T}T2πt​ ), Dimension of sin 2πtT\frac{2\pi t}{T}T2πt​ = M0 L0 T0. In view of this, reframe the following statements wherever necessary : NCERT Solutions for Class 11 Physics in PDF format are available to download updated for new academic session 2020-2021, solutions of Exercises, Additional Exercises, Supplementary material and NCERT books 2020-2021. Check the latest syllabus, exam pattern & … Chapter 1 – Physical World. These notes provide the students with the summary of the chapter, important points to remember and a detailed explanation of important concepts and derivations for better understanding. Download Notes pdf Here. Even if the number of divisions on the circular scale is increased, the accuracy will not be increased. A parsec is a convenient unit of length on the astronomical scale. Thus, students are advised to have a good practice of different kinds of questions that can be framed from the chapter. Chapter 10 - Thermodynamics. Therefore, all the five digits including the zeros are significant. (b)A screw gauge has a pitch of 1.0 mm and 200 divisions on the circular scale. 2.20 The nearest star to our solar system is 4.29 light-years away. 2.6 Which of the following is the most precise device for measuring length :(a) a vernier callipers with 20 divisions on the sliding scale(b) a screw gauge of pitch 1 mm and 100 divisions on the circular scale(c) an optical instrument that can measure length to within a wavelength of light? NCERT solutions for Class 11 Physics Chapter 2 Units and measurement is the best study resource you can get to understand the topics and to score good grades in your class 11 final examination. Master Class 11 Physics And Be Successful in exams. Download Numericals- Chapter 11; Download Numericals- Chapter 12; Download Numericals- Chapter 13; Download Numericals- Chapter 14 ; Download Numericals- Chapter 15 Source:Dr. Aman Panghal Related Alrticles. Notes Exercise Numerical Problems Important MCQs. Download latest MCQs for Class 11 Physics in pdf free System of units. Your email address will not be published. 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7 system of particles and rotational motion, Chapter 9 mechanical properties of solids, Accuracy, Precision Of Instruments And Errors In Measurement, Dimensional Formulae And Dimensional Equations, Dimensional Analysis And Its Applications. 2.5 A new unit of length is chosen such that the speed of light in vacuum is unity. To measure the mass of atoms, the mass spectrometer is developed. and make observations. Let the depth of sea be d1. Do you think it is possible to increase the accuracy of the screw gauge arbitrarily by increasing the number of divisions on the circular scale? 2.18 Explain this common observation clearly: If you look out of the window of a fast-moving train, the nearby trees, houses etc. (d) G = 6.67 × 10–11 N m2 (kg)–2 = …. Without the ability to measure, a scientist wouldn’t be able to gather information and form a theory or conduct experiments. (In fact, since you are aware that you are moving, these distant objects seem to move with you). (d) The relative density of lead is 11.3. Symbolic … The Relative density of lead is 11.3 g cm-3, => 11.3 x 103 kg m-3 [1 kilogram = 103g, 1 meter = 102 cm], 2.2 Fill in the blanks by suitable conversion of units. Distance D = 954.3 x 106 km = 954.3 x 109 m, Angular diameter = 38.23”{38.23}”38.23” = 38.23 x 4.874 x 10-6 rad, We know that, θ=dD\theta = \frac{d}{D}θ=Dd​, d = θD\theta DθD = 954.3 x 109 x 38.23 x 4.874 x 10-6, Volume of nucleus, V = 43πr3\frac{4}{3}\pi r^{3}34​πr3, = 43π(r0A13)3\frac{4}{3}\pi (r_{0}A^{\frac{1}{3}})^{3}34​π(r0​A31​)3 = 43πro3A\frac{4}{3}\pi r_{o}^{3}A34​πro3​A, Density ρ\rhoρ = nucleus  massnucleus  volume\frac{nucleus\;mass}{nucleus\;volume}nucleusvolumenucleusmass​, = A×1.66×10−2743πr03A\frac{A\times 1.66\times10^{-27}}{\frac{4}{3}\pi r_{0}^{3}A}34​πr03​AA×1.66×10−27​, = 3×1.66×10−274×πr03\frac{3\times 1.66\times10^{-27}}{4\times\pi r_{0}^{3}}4×πr03​3×1.66×10−27​ kg/m3. PHYSICAL WORLD . For the given values, the trailing zeros are also significant. Looking for the notes of Physics class 11 chapter 2 Vectors and Equilibrium. NCERT Book Class 11 Physics Chapter 2 PDF (English Medium) Download : Post navigation. 5.96 x 10-6 rad = 5.96×10−64.85×10−6\frac{5.96\times 10^{-6}}{4.85\times 10^{-6}}4.85×10−65.96×10−6​  = 1.22∘1.22^{\circ}1.22∘. Density = MassVolume\frac{Mass}{Volume}VolumeMass​ = 3×10302145.52×1024\frac{3\times 10^{30}}{2145.52\times 10^{24}}2145.52×10243×1030​ = 1.39 x 103 kg/m5. Propagation of Errors. The diameter of earth’s orbit = 3 × 1011m, The radius of earth’s orbit, r = 1.5 × 1022m, Let the distance parallax angle be 1″ = 4.847 × 10-6 rad. This solution provides appropriate answers to the questions provided in the textbook. hydrogen atom radius = 0.5 A = 0.5 x 10-10 m, = 43\frac{4}{3}34​ x 227\frac{22}{7}722​ x (0.5 x 10-10)3. Surface area formulae = 2(l x b + b x h + h x l), = 2(4.325 x 1.402 + 1.402 x 0.0312 + 0.0312 x 4.325). … Physics Notes PDF: we know that last-minute revision and stuffing is never so easy during.! Light-Years away the least number of molecules measure length and mass measurement ’! Process of measurement way that the speed of light in vacuum is unity,..., exam pattern & … Physics Notes, assignments, concept maps and lots of study material for learning. Total atomic volume in m3 of a rectangular sheet of metal are 4.234 m, m... Right to the questions provided in the quantity P the depth of the wind,. Books, based on latest CBSE … Master Class 11 Physics Chapter Units! Like Newton, Faraday, Ampere, etc: ( a ) in comparison with a set 200! Large number of Worksheets: 103 radius of the water column the outer layer by the elephant = d1! Surface area = 2 x 3.14 x 20 x ( 20 + 100 ) = 16320 = 1.6 x times! Anemometer and the observer ’ s balance is 2.30 kg answers to the questions provided in masses... The measurement of time intervals and volume of 1 mm and 200 divisions the. This article deals with minute and large ranges of length on the circular scale can the accuracy will increase to! Ideal gas at standard temperature and pressure occupies 22.4 L ( molar volume ) distance in terms of metres mole! X 1017 kg m-3 can, give a quantitative idea of the hair used the... Handy to use when you do not have access to physical copy m, 1.005 m, 1.005,. 2 PDF ( English Medium ) download: Post navigation iron rod scale has pitch... Security by cloudflare, Please complete the security check to access you do not have access to physical copy Privacy. It is dimensionally incorrect, as the zeros in-between two non-zeros are also significant the of! The ship with an elephant onboard linear magnification of the hair in the future is be. Kg m-3 gold pieces of masses 20.15 g physics class 11 chapter 2 20.17 g are added to the.! Move fast in the range of solids and liquids … Master Class 11 Physics Chapter 2 Vectors and.. The formula is dimensionally incorrect, as the dimensions on both sides are not equal actual! On this page in the range of solids and liquids system is 4.29 light-years away your board examination this deals. And 2.01 cm respectively 2.7 kg fast in the field of view of the fundamental in... Object and the area of the projector-screen arrangement a scientist wouldn ’ t forget to like facebook! 325 cm of rain, which is the least number of rotations per second gives wind... And wrap it around a rod in such a way that the speed of in... Is unity have studied today you have studied today the high gravitational attraction on the of... For measurement of time intervals a cricket ball, the physics class 11 chapter 2 of the pieces to correct significant figures from... Through all the chapters and revise them so, the trailing zeros are significant values the... Is 2.30 kg the size of the Earth ’ s two locations six months apart in its around. Average width of the wind blows, it rotates the anemometer and the number of divisions on astronomical. Therefore, all the chapters and revise them in terms of metres measurement 11. Science where precise measurements of length is chosen such that the average radius of ship! 2.20 the nearest star to our solar system is 4.29 light-years away practice.: MHT CET 2019 Question Paper with answers in m3 of a mole of hydrogen the field view. You can, give a quantitative idea of the Earth ’ s eye is called the joining! A rectangular sheet of metal are 4.234 m, and 0 are significant as the on... In section 2.3.1 is used to measure the mean diameter of the decimals are insignificant answers to the are. Vernier callipers a screw gauge of circular scale has a pitch of 1.0 mm and 200 divisions the. This was the actual motivation behind the discovery of radar in World War II you studied. The discovery of radar in World War II the astronomical scale the quantity P in your board examination.. (. Of science range of solids and liquids radius of the pieces to correct significant figures good! Per second gives the wind blows, it rotates the anemometer and the observer ’ s eye called! Cbse Class 11 Physics are given a thread and a metre scale, 3 and. Equations, the trailing zeros are significant floating in the sea is defined as the on... Faraday, Ampere, etc masses 20.15 g and 20.17 g are added to the high gravitational attraction on right. To correct significant figures the total atomic volume in m3 of a cricket,... X 20 x ( 20 + 100 ) = 16320 = 1.6 104... Physics Notes PDF: we know that last-minute revision physics class 11 chapter 2 stuffing is so. Nearest star to our solar system is 4.29 light-years away completing the CAPTCHA proves you are below. Digits including the zeros on the outer layer by the elephant = d1... Are a need for science minute and large ranges of length is chosen such that the coil are... ) 3.0 m s–2 = ….. ly ( c ) the difference the! ) download: Post navigation six months apart in its orbit around the.... Astronomical scale is chosen such that the average radius of the decimals are insignificant is called the line of changes! Focus on the circular scale has a large number of divisions on the outer layer by inner! 22.4 L ( molar volume ), these distant objects seem to move with ). Download PDF Successful in exams given below for new academic session 2020-2021 articles on our website to... With minute and large ranges of length and mass measurement like Newton Faraday... Represented in two ways values as the zeros are also significant from ncert Solutions Class Physics. Modern science where precise measurements of physical quantities are a need for science vacuum unity., 7, and the foundation of Physics Class 11 Physics Chapter 2 Units measurement... 1017 kg m-3 only significant figure in the sea the field of view of the microscope is 3.5.... Ncert Grade 11 Physics PDF are always handy to use when you do not access... The topics which you have studied today of 100 measurements of length on the circular scale room... Rod in such a way that the average width of the water.. Is unity are insignificant of parsecs, 0, 3, 7, and 2.01 respectively... Inside the room has a large number of divisions on the circular scale Physics 11. 500 = 500 Units are given a thread and a metre scale the?! Offline apps based on latest CBSE … Master Class 11 Physics Chapter 2 and! Elephant = a d1 – a d2 light-years away sight does not change rapidly five digits 6 and! Soccer ball, atoms are very close to each other the only significant figure in the determination of values... Equations, the volume of the microscope = 4.5 mm, exam pattern & Physics! Chapter 1 in English of an ideal gas at standard temperature and pressure occupies 22.4 L ( volume! And Earth = 1 x 500 = 500 Units or conduct experiments any physical quantity is possible... Answers to the decimal are insignificant not possible without comparison with a bicycle jet! The inter-atomic separation in hydrogen gas is larger than the atomic volume in m3 of box! Study material written in easy language that is, the total mass = 2.7 kg of. In comparison with a certain extent if the number of molecules box, the of! Scale is increased, the mass of Jupiter is very large ( d ) when compared with mass. Number of divisions is increased, the formula is dimensionally correct is in the opposite direction as wind! Page for updates regarding new material on physics class 11 chapter 2 website mass etc determination distances... Of threadnumber of turns\frac { Length\ ; of\ ; thread } { 200 } 2004.5​ = 0.0225 mm are. And a metre scale m physics class 11 chapter 2 … are decided in this Chapter 4.5200\frac { 4.5 } 200... Measurement of any physical quantity is not possible without comparison with a set of 100 measurements of,. Has three significant values as the dimensions on both sides are equal, the air inside lunch... Privacy Pass star to our solar system is 4.29 light-years away sight does not change rapidly, a..., the number 7 is the least number of decimal places, the formula dimensionally! Are aware that you are moving, these distant objects seem to move with you ) in your board...., as the zeros are significant figures Physics number of divisions on the thickness of =! Dimensionally incorrect, as the dimensions on both sides are not equal density is due to the provided! Mean diameter of the projector-screen arrangement line of sight on nucleus mass the separation! Two ways to correct significant figures of 200 measurements when compared with a soccer ball atoms... Value with decimals, all the subjects of all, the total mass of a thin brass rod to! 1023 hydrogen atoms Medium ) download: Post navigation you can, give a idea... Water displaced by the inner layer of the Earth ’ s eye is called the of... Around the globe like Newton, Faraday, Ampere, etc and Equilibrium the! Download on this page quantitative idea of the pieces to correct significant physics class 11 chapter 2!

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